Produce a list of members, along with the number of hours they've booked in facilities, rounded to the nearest ten hours. Rank them by this rounded figure, producing output of first name, surname, rounded hours, rank. Sort by rank, surname, and first name.
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Expected Results

firstname surname hours rank
Darren Smith 340 2
Tim Rownam 330 3
Tim Boothe 220 4
Tracy Smith 220 4
Gerald Butters 210 6
Burton Tracy 180 7
Charles Owen 170 8
Janice Joplette 160 9
Anne Baker 150 10
Timothy Baker 150 10
David Jones 150 10
Nancy Dare 130 13
Florence Bader 120 14
Anna Mackenzie 120 14
Ponder Stibbons 120 14
Jack Smith 110 17
Jemima Farrell 90 18
David Pinker 80 19
Ramnaresh Sarwin 80 19
Matthew Genting 70 21
Joan Coplin 50 22
David Farrell 30 23
Henry Worthington-Smyth 30 23
John Hunt 20 25
Douglas Jones 20 25
Millicent Purview 20 25
Henrietta Rumney 20 25
Erica Crumpet 10 29
Hyacinth Tupperware 10 29

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Answers and Discussion Show

select firstname, surname,
	((sum(bks.slots)+10)/20)*10 as hours,
	rank() over (order by ((sum(bks.slots)+10)/20)*10 desc) as rank

	from cd.bookings bks
	inner join cd.members mems
		on bks.memid = mems.memid
	group by mems.memid
order by rank, surname, firstname;          

This answer isn't a great stretch over our previous exercise, although it does illustrate the function of RANK better. You can see that some of the clubgoers have an equal rounded number of hours booked in, and their rank is the same. If position 2 is shared between two members, the next one along gets position 4. There's a different function, DENSE_RANK, that would assign that member position 3 instead.

It's worth noting the technique we use to do rounding here. Adding 5, dividing by 10, and multiplying by 10 has the effect (thanks to integer arithmetic cutting off fractions) of rounding a number to the nearest 10. In our case, because slots are half an hour, we need to add 10, divide by 20, and multiply by 10. One could certainly make the argument that we should do the slots -> hours conversion independently of the rounding, which would increase clarity.

Talking of clarity, this rounding malarky is starting to introduce a noticeable amount of code repetition. At this point it's a judgement call, but you may wish to factor it out using a subquery as below:

select firstname, surname, hours, rank() over (order by hours desc) from
	(select firstname, surname,
		((sum(bks.slots)+10)/20)*10 as hours

		from cd.bookings bks
		inner join cd.members mems
			on bks.memid = mems.memid
		group by mems.memid
	) as subq
order by rank, surname, firstname;
You'll need the RANK window function again. You can use integer arithmetic to accomplish rounding.

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