Produce a count of the number of facilities that have a cost to guests of 10 or more.
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select count(*) from cd.facilities where guestcost >= 10;          

This one is only a simple modification to the previous question: we need to weed out the inexpensive facilities. This is easy to do using a WHERE clause. Our aggregation can now only see the expensive facilities.

You'll need to add a WHERE clause to the answer of the previous question.

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